(x-7)(x+2)=x^2+10

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Solution for (x-7)(x+2)=x^2+10 equation: 


Simplifying
(x + -7)(x + 2) = x2 + 10

Reorder the terms:
(-7 + x)(x + 2) = x2 + 10

Reorder the terms:
(-7 + x)(2 + x) = x2 + 10

Multiply (-7 + x) * (2 + x)
(-7(2 + x) + x(2 + x)) = x2 + 10
((2 * -7 + x * -7) + x(2 + x)) = x2 + 10
((-14 + -7x) + x(2 + x)) = x2 + 10
(-14 + -7x + (2 * x + x * x)) = x2 + 10
(-14 + -7x + (2x + x2)) = x2 + 10

Combine like terms: -7x + 2x = -5x
(-14 + -5x + x2) = x2 + 10

Reorder the terms:
-14 + -5x + x2 = 10 + x2

Add '-1x2' to each side of the equation.
-14 + -5x + x2 + -1x2 = 10 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-14 + -5x + 0 = 10 + x2 + -1x2
-14 + -5x = 10 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-14 + -5x = 10 + 0
-14 + -5x = 10

Solving
-14 + -5x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + -5x = 10 + 14

Combine like terms: -14 + 14 = 0
0 + -5x = 10 + 14
-5x = 10 + 14

Combine like terms: 10 + 14 = 24
-5x = 24

Divide each side by '-5'.
x = -4.8

Simplifying
x = -4.8

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